Question

If you have 6.022*10²³ ions of Al; how many sulphate ions will be required to prepare AL²(so⁴)³​

Answer 1

Answer:

AL²(so⁴)³

for every 2 moles of al 3 moles of sulphate is req.

if there is 1 mole of al then we requaire (3*1) /2=1.5 moles