If you have 7 identical coins,out of which 6 coins are heavier than that of the remaining 1. How would you find that coin if the only thing you have is a weighing machine(not electrical)...which has place to keep objects on both sides!
But you can weigh only 2 times
Answers
Divide the coins in two equal groups(that is of 3 coins each) and separate the left out 7th coin
In your first turn
Check which group is heavier by using a physical balance
If the physical balance is in equilibrium then the left coin is the heavier one
Else
Take the heavier group and separate all the 3 coins
In your second turn
Place any two coins one on each side of physical balance
If the physical balance is in equilibrium then the coin kept out side is the heavier one
If the physical balance is not in equilibrium then the lower side of the physical balance has the heavier coin
Hope it HELPS
Plzzzz mark as BRAINLIEST !
Answer:
First, divide the coins in three groups consisting of 2, 3 and 2 each.
Now weigh those two groups consisting 2 coins each. If any one group weighs more, then weigh those two coins of that group individually.
If both weigh same, then leave them and weigh any 2 coins from the third group. The one which will be heavier is the odd one out. Or if both weigh same, then the left over coin is the odd one out.
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