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time taken by pipe to fill = 3 hrs
time taken in 1 hr = 1÷3
due to leak time taken by tank to empty = x hrs
leak in 1 hr = 1÷x
net time to fill = 7÷2
tank filled in 1 hr = (7÷2)÷1 = 2÷7
therefore( 1÷3)-(1÷x)=2÷7
= 21 hrs
time taken in 1 hr = 1÷3
due to leak time taken by tank to empty = x hrs
leak in 1 hr = 1÷x
net time to fill = 7÷2
tank filled in 1 hr = (7÷2)÷1 = 2÷7
therefore( 1÷3)-(1÷x)=2÷7
= 21 hrs
aaryana45:
thanks
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