Question

If you have mind then solve this.

Answer 1

Answer:

Option B is the answer.

Step-by-step explanation:

Let largest circle be c1, smaller be c2 and smallest be c3

Then,

➡️ We see that circle is divided into 4 equal parts by intersection of diameters. (since diameter always divide circle into two equal halves)

So u see,

➡️ If we move the shaded portion of c2 to 1 quadrant, and shaded portion of c3 to 1 quadrant. (no change will be their on area if we consider the similar parts corresponding to shaded parts as all these will have equal area)

Then,

➡️ Area of shaded portion = area of quadrant of c1.

Area of shaded portion = 1/4 pi r1 ^2

Area of shaded portion = pi ☓ 1/4 ☓ (21)^2 sq. cm

Area of shaded portion = pi ☓ 1/4 ☓ 441 sq. cm

Area of shaded portion = 441/4 ☓ pi sq. cm.

➡️ Or area of shaded portion =

441 pi/4.sq. cm

Answer : option (b) 441/4 pi sq. cm

Answer 2

$\textsf{\underline{From the Figure :}}\\\\\\\textsf{We can Notice that : Area of the Shaded part is equal to the Area of One} \\ \textsf{Quarter of the Circle with Radius 21 cm}\\\\\\\sf{We\;know\;that} : \boxed{\sf{Area\;of\;Circle = \pi r^2}}\\\\\\\sf{\implies Area\;of\;One\;Quarter\;of\;Circle = \dfrac{\pi r^2}{4}}\\\\\\\sf{\implies Area\;of\;Shaded\;part = \bigg(\dfrac{\pi \times (21)^2}{4}\bigg)\;sq.cm}$

$\sf{\implies Area\;of\;Shaded\;part = \dfrac{441(\pi)}{4}\;sq.cm}$