Question

If you have weather balloon with a volume of 5,678 liters, how many grams of helium could it hold?

Answer 1

If the cylinders were at 1.00 atm, they would contain 50.00 L each, so at 100.0 atm they contain 5000. L each.

1m³ =1000L,

So 100.0m³=1.000×10^5L.

Since the pressure in the balloon is only 0.10 atm, though, the gas volume equals only 1.000×10^4

Lat 1 atm.

(1.000 × 10⁴ L) / (5000. L/cylinder) = 2.00 cylinders.

5000L

1.000×10^4L/cylinder =2 cylinders

________________________________