Question

if you immerse an object in water at 4 degree celsius,what will be the weight loss of the object,whose radius is 14cm and density is 4000 kg/m^3​

Answer 1

Answer According to Archimedes' principle, when an object is wholly or partially immersed in a liquid, it experiences a buoyant force which is equal to the weight of liquid displaced by the object.

The buoyant force acting on the ball, F = Volume of the ball × density of water × acceleration due to gravity

Volume of the ball =Mass of the ball/ Density of the ball

                         =4 kg/4000 kg/m3

                         =0.001m3  

The buoyant force acting on the ball, F = 0.001m3 × 1000 kg/m3 × 10 m/s2

F = 10 N

The buoyant force acting on the ball = 10 N

The weight of the ball = 4 kg×10m/s2 = 40 N

The apparent weight of the ball in water = 40 N - 10 N