if you increase the length and width of a rectangle by 50%. Find the ratio of it's new area to original area
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Answered by
1
LET THE ORIGINAL LENGTH BE L
AND
ORIGINAL BREATH BE B.
ORIGINAL AREA = LB
LENGTH INCREASED BY 50% = 150 L / 100
BREATH INCREASED BY 20% = 120 B / 100
INCREASED AREA = 150 L X 120 B / 100 X 100
= 18000 LB / 10000
= 1.8 LB
NOW,
1.8 LB / LB = 1.8
CHANGING 1.8 INTO FRACTION.
1.8 = 18/10 = 9/5
SO,
THE INCREASED AREA WILL BE 9/5 TIMES OF THE ORIGINAL AREA.
PLZ MARK IT AS BRAINLIEST ANSWER AND DROP A ♥!!!!!!!!
khushi1209:
But the answer is 9 is to 4
I know the answer
????
actually u have increased the breadth by 20% only.. in the question u have to increase it by 50% see next answer
ur method is so typical
we can easily get it by taking length and breadth 100cm
length and breadth with cancel each other at the end... so we can leave them undefined for easy calculations... if u dont want to calculate much..
will*
i mean they both will get canceled at the end :-/
OK...
Answered by
1
previous area a = L* B ((equation 1)
new Length = 1.5 L
( L + 50% of L or L + 0.5L)
new Breadth = 1.5 B
New Area A = 1.5 L * 1.5 B (equation 2)
by dividing equation 1 by 2
A/a = 1.5 * 1.5 * L * B / (L * B)
A/a = 2.25
A /a= 225/100
ratio = 9/4
answer is 9/4 ..
mark as brainliest plz
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