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siddhartharao77:
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Given length of a room = 8m 25cm
= 825cm.
Given breadth of a room = 6m 75cm
= 675cm.
Given height of room = 4m 50cm
= 450cm.
Now,
We need to find the HCF of 825,675,450.
Prime factorization of 825 = 3 * 5 * 5 * 11
Prime factorization of 675 = 3 * 3 * 3 * 5 * 5
Prime factorization of 450 = 2 * 3 * 3 * 5 * 5
HCF(825,675,450) = 5 * 5 * 3
= 75.
Therefore the longest rod which can measure the three dimensions = 75cm.
Hope this helps!
= 825cm.
Given breadth of a room = 6m 75cm
= 675cm.
Given height of room = 4m 50cm
= 450cm.
Now,
We need to find the HCF of 825,675,450.
Prime factorization of 825 = 3 * 5 * 5 * 11
Prime factorization of 675 = 3 * 3 * 3 * 5 * 5
Prime factorization of 450 = 2 * 3 * 3 * 5 * 5
HCF(825,675,450) = 5 * 5 * 3
= 75.
Therefore the longest rod which can measure the three dimensions = 75cm.
Hope this helps!
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