Question

if you know pls answer to the question

Answer 1

In the figure it is given that ∆ADE is an isosceles ∆
so angle AED=Angle ADE
so angle ABD=angle AED are equal! becuase both have their supplement ary angle same
so the sides AC and AE are equal
Now in ∆ABD and∆ AEC
angle ABD= angle AEC
AD=AE
BD = EC. given

so ∆ADB≈∆AEC

Now adding ∆ADE to both sides

so ∆ADB+∆ADE≈∆AEC+∆ADE
∆ABE≈∆ACD



[here ≈ is equal to congruent sign]