Question

if you know so please give me solution it's too urgent ​

Answer 1

Answer:

from the given figure EF II CD as angle CEF =angle ECD.(co interior angles)

145° + 35° = 180°

therefore EF II CD

AB II CD

as angle ABC = angle BCD

65°=angle BCE + angle ECD

65° = 30° + 35°

65° = 65° (alternate interior angles)

therefore AB II CD , EF II CD

Hence AB II CD II EF.

HENCE PROVED...