Question

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Answer 1

Answer:

Total force on q = ( √2 + 1 ) / 4πε₀ Q q / R²

Explanation:

Solution---->

1) Plz see the attachment

2) We know that, same type of charges repel each other and opposite charges attract each other so all five charges placed on semicircle applied same magnitude repulsive force on charge q at centre of semicircle but direction of all forces are different .

3) We know that electrostatic force between two charges q₁ and q₂ seperated by distance r is

F = 1 / 4π ε₀ ( q₁ q₂ / r² )

3) We know that ||gm law of vectors is

R² = P² + Q² + 2PQ Cosθ

Where θ is angle between P an Q .

4) Resultant of two equal magnitude vector bisected angle between them

5) Since charges Q are placed equidistant then

∠ AOB = ∠ COB = ∠ DOC = ∠ EOD = 180°/4 = 45°

So , ∠ BOD = 45° + 45° = 90°

So, angle between F ( D ) and F ( B ) = 90°