Question

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Answer 1

Answer:

the answer is $\frac{12}{7}$

Step-by-step explanation:

$(3^{-1} + 4^{-1} )^{-1}$ ------------------- (this is the question)

$(\frac{1}{3} +\frac{1}{4} )^{-1}$ ----------------------(∵ $a^{-1} = \frac{1}{a}$ so,( $a^{-1} + b^{-1} = \frac{1}{a} + \frac{1}{b}$ ))

$(\frac{4+3}{12})^{-1}$ -----------------------( cross multiplication)

$(\frac{7}{12} )^{-1}$ ----------------------(this equation is in the form of $(\frac{a}{b} )^{-1}$)

$\frac{7^{-1} }{12^{-1} }$ ------------------------(∵ $(\frac{a}{b} )^{-1} = \frac{a^{-1} }{b^{-1} }$ )

$\frac{12}{7}$ ----------------------($\frac{a^{-1} }{b^{-1} }$ now, apply $a^{-1} = \frac{1}{a}$)

so,∴ the answer is $\frac{12}{7}$

PLS MRK AS BRAINLIEST PLSSSSSSSSSS..................... :)

Answer 2

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