if you know this pls answer this fast
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Answer:
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1. Let the angle be 'x'.
Given, supplementary angles are in the ratio 2:3
⇒ 2x + 3x = 180°
5x = 180°
∴ x = 180° ÷ 5
⇒ x = 36°
Substituting x, we get:
2x = 2(36) = 72°
3x = 3(36) = 108°
Hence the two angles are 72° and 108°.
2. Let the angle be 'x'
Given, complementary angles are in the ratio 4:5
∴ 4x + 5x = 90°
9x = 90°
⇒ x = 90° ÷ 9
∴ x = 10°
Substituting x, we get:
4x = 4(10) = 40°
5x = 5(10) = 50°
Hence, the two angles are 40° and 50°.
3. 150 + x = 180 [Linear pair]
x = 180 - 150
∴ x = 30°
Hence the angles are x = 30°, 3x = 90°, and 3x = 90°.
4. Given, x = 25°
⇒ 3x = 3(25) = 75°
Now, 75° + (2y + 5)° = 180° [Linear pair]
80 + 2y = 180
2y = 180 - 80
y = 100 ÷ 2
∴ y = 50°