Math, asked by siddharthbarad1107, 8 months ago

if you need a right handed screw from a box containing 20 right handed and 5 left handed screws. what is the probability that you get at least one right handed screw in drawing 2 screws with replacement​

Answers

Answered by yogitajangid2060
0

Answer:

baggie oxbow. hauxiwjahz

Answered by annasl
0

Answer:

probability of getting at least one right handed screw in drawing 2 screws with replacement​ = 0.96

Step-by-step explanation:

given: there are 20 right handed screws and 5 left handed screws

total 25 screws

to find: probability of getting at least one right handed screw in drawing 2 screws with replacement​

P[event] = \frac{number\ of \favorable\ cases}{ total \ number \ of\  outcomes}

here, probability of getting at least one right handed screw in drawing 2 screws with replacement​ = 1 - probability of not getting 2 right handed screws

probability of not getting 2  right handed screws =  \frac{5}{25} ×  \frac{5}{25}

P[E] = 1 - \frac{5}{25} ×  \frac{5}{25}

         = 1 - \frac{25}{625}

         = \frac{625-25}{625}

        = \frac{600}{625}

        = \frac{24}{25}

        = 0.96

probability of getting at least one right handed screw in drawing 2 screws with replacement​ = 0.96

Similar questions