Question

If you normally weigh 706 N, what is your apparent weight if you are in an elevator that is slowing down at the rate of 1.65 m/s2?

Answer 1

Answer:

589.51N

Explanation:

Weight=mg, So 760=m(10)

m=70.6kg

if lift is decelerating, then, W=m(g-a)

W=70.6(10-1.65)

W=70.6(8.35)

W=589.51N