Hindi, asked by nikeetajohnson16, 1 month ago

If you restore a ship piece by piece, is it the same ship?​

Answers

Answered by OoINTROVERToO
1

NO

Explanation:

FORMULAE OF DIFFERENTIATION ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

  \tt{\dfrac{d}{dx} x^{n} = nx^{n-1}}

  \tt{\dfrac{d}{dx} (constant) = 0} ⠀

 \tt{\dfrac{d}{dx} kf(x) = k. \dfrac{d}{dx} f(x)}

 \tt{\dfrac{d}{dx} (u+v) = \dfrac{du}{dx} + \dfrac{dv}{dx} } ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

  \tt{\dfrac{d}{dx} (u-v) = \dfrac{du}{dx} - \dfrac{dv}{dx}}  ⠀⠀⠀⠀⠀⠀⠀⠀⠀

 \tt{\dfrac{d}{dx} (u.v) = u \dfrac{dv}{dx} + v \dfrac{du}{dx}} ⠀⠀⠀⠀⠀⠀

 \tt{\dfrac{d}{dx} (\dfrac{u}{v}) = \dfrac{v \dfrac{du}{dx} - u \dfrac{dv}{dx}}{v^2}}

  \tt{\dfrac{d}{dx} (Cos x) = - sin x}

  \tt{\dfrac{d}{dx} (Sin x) = Cos x}

  \tt{\dfrac{d}{dx} (Tan x) = Sec^2 x}

  \tt{\dfrac{d}{dx} (Cot x) = - Cosec^2 x}

  \tt{\dfrac{d}{dx} (Sec x) = Sec x. Tan x}

  \tt{\dfrac{d}{dx} (Cosec x) = - Cosec x. Cot x}

  \tt{\dfrac{d}{dx} log_{e}(x) = \dfrac{1}{x}}

 \tt{\dfrac{d}{dx} e^x = e^x} ⠀⠀⠀⠀⠀

  \tt{\dfrac{d}{dx} a^x = a^{x} . log_{e}{a}}

Answered by arpraba1986
1

Answer:

23 Ship of Theseus

Plutarch asked whether a ship that had been restored by replacing every single wooden part remained the same ship. The paradox had been discussed by other ancient philosophers such as Heraclitus and Plato prior to Plutarch's writings, and more recently by Thomas Hobbes and John Locke.

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