Science, asked by shanyaaaa11, 1 month ago

If you rewrite the following word equation as a balanced chemical equation, what will the coefficient and symbol for iodine be? bromine + potassium iodide  potassium bromide + iodine

Answers

Answered by mahighagargunde
0

Answer:

a) Potassium bromide(aq) + Barium iodide(aq) → Potassium iodide(aq) + Barium bromide(s)

2KBr

(aq)

+BaI

2

(aq)

→2KI

(aq)

+BaBr

2

(s)

In this reaction, both the reactants exchanges ions to for two new products, hence, it is a double displacement reaction

(b) zinc carbonate(s) → Zinc oxide(s) + Carbon dioxide(g)

ZnCO

3

(s)

→ZnO

(s)

+CO

2

(g)

In this reaction, a single substance yields two different product. hence, it is a decomposition reaction

(c) Hydrogen(g) + Chlorine(g) → Hydrogen chloride(g)

H

2

(g)

+Cl

2

(g)

→2HCl

(g)

In this reaction, two different reactants react with each other to form a single product. Hence, it is called a combination reaction

(d) Magnesium(s) + Hydrochloric acid(aq) → Magnesium chloride(aq) + Hydrogen(g)

Mg

(s)

+2HCl

(aq)

→MgCl

2

(aq)

+H

2

(g)

In this reaction, more reactive Mg is replacing less reactive H. Hence, it is displacement reaction

Answered by pruthaasl
0

Answer:

The coefficient of iodine will be 1 and its symbol will be I_{2}.

Displacement Reactions:

  • A reaction in which an atom or group of atoms is replaced by another atom or group of atoms is called a displacement reaction.
  • In other terms, a more reactive element is replaced by a less reactive element.
  • The general equation for a displacement reaction is as follow: A + BC → AC + B, where B is being replaced by A in the BC compound.
  • Example: Iron reacts with copper sulfate to give iron sulfate and copper as the products

Explanation:

The given word equation is

bromine + potassium iodide → potassium bromide + iodine

Rewriting the given word equation as a chemical equation.

Br_{2} + KIKBr + I_{2}

Balancing the above chemical equation, we get

Br_{2}+2KI2KBr + I_{2}

Therefore, the coefficient of the iodine on the product side is 1 and the symbol is I_{2} since it is a diatomic molecule.

#SPJ2

Similar questions