If you roll a 10-slided dice 3 times, what is the probability that they form neither a strictly increasing nor a strictly decreasing series?
Answers
Answered by
0
Answer:
0.76
Explanation:
Answered by
0
Answer:
0.76
Explanation:
Let the number of strictly increasing arrangements be = X
Let the number of strictly decreasing arrangements be = Y
Let the number of neither the strictly decreasing nor strictly increasing be = Z
Thus ,
X+Y+Z=1000
A strictly increasing arrangement from the opposite side, will look like a strictly decreasing arrangement.
Thus, X=Y
= 2X+Z=1000
For an increasing arrangement ,all the three numbers should be different which can be done in 10C3 ways.
Z = 1000- 10C3 × 2
= 760
Thus, the probability
= 760/1000
= 0.76
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