if you rolled a dice 48 times, how many times would you predict not to roll a six
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Answered by
0
Answer:
Step-by-step explanation:
According to me, p(not e)= 1-p(e)
So p(e) = 1/48
P(not e)= 1-1/48
=48/48-1/48
=47/48
Hope this helps you!
Answered by
0
Answer:
for 48 times will be 48x6 i.e. 288 will be its total chances
for not to roll six will be 1+2+3+4+5 =15
and thus 15/288
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