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p=mv
=m×root 2gh
=m root2gh in upwards direction
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Answer:
2m√2gh - Option(C)
Explanation:
The marble is dropped from height h then the velocity of the marble on reaching the ground is √2gh
Since it is given that it rebounds to the same height after striking the ground
. Hence the change in velocity will be given as:
Δv = √2gh - (-√2gh)
Hence the change is velocity is 2√2gh
Therefore change in momentum = m * ( change in velocity ) .
= m(2√2gh)
= 2m√2gh
Hope it helps!Brainliest it Brother
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