if you started from your home to school moves 3m towards east then 4m towards north what is distance and displacement in both cases
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Answer:
The person travelled a total distance of (4 + 3) metres = 7 metres.
Remember, distance is a scalar quantity, which has only magnitude. But, displacement is a vector quantity, which has magnitude and direction both.
First the person walks 4 Kms East, then 3 Kms North. So, magnitude of displacement = [√{(4^2) + (3^2)}] metres = 5 metres. And, direction of displacement: In North East direction, making an angle {arc tan (4 / 3)} ≈ 53.13° with the North - South line passing through the starting point.
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Answer:
distance =( 4+3)m=7m and displacement can be found by Pythagoras theorem x^2=16+9=25
Explanation:
x=5m. :here x is the displacement
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