Math, asked by adityasciencegroup, 8 months ago

If you subtract (-8) from a number and multiply the result by 2, you get 16, what is the number?​

Answers

Answered by Anonymous
11

Given:

  • (-8) is subtracted from a number.
  • Then number multiplied by 2.
  • The result becomes 16 .

To Find:

  • The that unknown number.

Concept Used:

  • We will use linear equations to solve the question.

Solution:

Let us take the number be x .

Firstly number is subtracted (-8)

i.e. \sf{x-(-8)}

=\sf{x+8}

Secondly number is multiplied by 2 .

i.e. \sf{2\times(x+8)}

=\sf{2(x+8)}

But it's given that result is 16 .

So, ATQ,

\sf{\implies 2(x+8)=16}

\sf{\implies 2x+16=16}

\sf{\implies 2x=16-16}

\sf{\implies 2x=0}

\sf{\implies x=\dfrac{0}{2}}

{\underline{\boxed{\red{\sf{\longmapsto x=0}}}}}

Hence the required number is 0 .

Answered by Blossomfairy
4

Given :-

  • Subtract the (-8) from a number.
  • Then multiply the result by 2.
  • Then we will get 6.

To find :-

  • The number which we will get.

___________________________....

  • Let the number be x

According to the question,

  • x - ( -8) = ( x + 8 )
  • Multiply the number by 2 means = 2( x + 8)
  • Result is 16.

 \implies \sf \red {2  \: ( x + 8 ) = 16} \\  \sf \implies{2x \:  + 16 = 16 } \\  \implies \sf{2x = 16 - 16} \\  \implies \sf{ 2x = 0} \\  \implies \sf{x =  \frac{0}{2} } \\  \therefore \sf \pink{x = 0}

______________________....

\sf\blue{Verification\: :}

\sf{Putting\:the\:value\:of\:x}

2 ( x + 8 ) = 16

2 ( 0 + 8 ) = 16

2 × 8 = 16

16 = 16

\therefore\sf{Verified}

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