Question

If you want to change the temperature of 1 g of water from 273 K to 274 K,
how much energy is required ?​

Answer 1

Answer:

4.18 J or 1 calorie

Explanation:

Heat Energy Required = mcΔt

here, m = 1 g

Δt = 274 K - 273K = 1 K

c = 4.18 J / g

So, Energy Required = 1 * 4.18 * 1 = 4.18 J or 1 calorie

Answer 2

Answer:

To change the temperature of 1 gram of water from 273 K to 274 K, you need to add 4.184 joules of energy to the system.

Explanation:

To change the temperature of 1 gram of water from 273 K to 274 K, you need to add 4.184 joules of energy to the system because the specific heat capacity of water is 4.184 J/g•K, which means that it takes 4.184 joules of energy to raise the temperature of 1 gram of water by 1 kelvin.

Specific heat capacity

Specific heat capacity is a measure of the amount of heat energy required to raise the temperature of a substance by 1 degree Celsius or 1 kelvin. It is usually expressed in units of J/g°C or J/g•K.

Different substances have different specific heat capacities. For example, water has a high specific heat capacity and metals have low specific heat capacities.

To learn more about Specific heat capacity, refer these links.

https://brainly.in/question/142972

https://brainly.in/question/4369862

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