Question

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Answer 1

Answer:

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Answer 2

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39. i:

In ∆ABD and ∆ACD,

AB = AC ( two sides of an isosceles triangle i.e. ∆ABC are equal )

AD = AD ( Common Side )

BD = CD ( two sides of an isosceles triangle i.e. ∆BCD are equal )

Hence, ∆ABD is congruent to ∆ACD by SSS congruency rule.

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39. ii:

In ∆ABP and ∆ACP,

AB = AC ( two sides of an isosceles triangle i.e. ∆ABC are equal )

Angle ABP = Angle ACP ( Theorem 7.2 )

AP = AP ( Common Side )

Hence, ∆ABP is congruent to ∆ACP by SAS congruency rule.

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39. iii:

We know that ∆ABP and ∆ACP are congruent so,

Angle BAP = Angle CAP ( By C.P.C.T. )

Hence, AP bisects A or AP is the perpendicular bisector of BC.

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