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the areas of three adjacent faces of a cuboidical box are 120 cm^2, 72cm^2, 60cm^2 . find the volume of the box.
please is the answer with method.......
Answers
Answered by
1
areas of faces =Ib+bh+ Ih
so, 120=Ib
72=bh
60=1h
multiply all three I^2b^2h^2=518400
Ibh=720
so, 120=Ib
72=bh
60=1h
multiply all three I^2b^2h^2=518400
Ibh=720
Answered by
1
OK we have
Given
L X b = 120cm²
B X h = 72cm² [ .......(1)]
H X L= 60cm²
we know
vol = L X b X h
v² = L² X b² X h²
v² = L X L X b X b X h X h
v²= (L X b) X ( b X h ) X ( h X L )
V²= 120 X 72 X 60 ........... bcoz of eqn (1)
v²= 518400
V²= 720 ²
v =720 cm³
if u like it
mark as brainliest
thku
Given
L X b = 120cm²
B X h = 72cm² [ .......(1)]
H X L= 60cm²
we know
vol = L X b X h
v² = L² X b² X h²
v² = L X L X b X b X h X h
v²= (L X b) X ( b X h ) X ( h X L )
V²= 120 X 72 X 60 ........... bcoz of eqn (1)
v²= 518400
V²= 720 ²
v =720 cm³
if u like it
mark as brainliest
thku
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