If you wish to increase the amount of current in a resistor from 120 mA to 160 mA by changing the 24 V source, what should the new voltage setting be?
(A) 8 V
(B) 320 V
(C) 3.2 V
D) 32 V
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The voltage is 32 V.
Explanation:
Resistance from 120 m.A to 160 m.A
Voltage = 24 V
So the value of resistance is = 24/ [120 x (10-3)]
= 200 ohms
Now we calculate the new voltage at 200 ohms and current value of 160 m.A
V = IR
V = 200 x 160 = 32,000 m.V
V = 32 V
Thus the voltage is 32 V.
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