Question

If you wish to locate an electron in an atom within a distance of

0.1Å. What is the uncertainty involved in the measurement of its

velocity?​

Answer 1

The uncertainity involved in the measurement of velocity is Δ v ≥ 5.79 x 10^6 m/s.

Explanation:

According to Heisenberg's uncertainity principle:  

Δ x.Δ p ≥ h/4π

Δ p = m Δ v

Δ v = Δ p / m

Δ v  ≥ h /4πmΔx

Here "h" is the plank's constant.

Now put the values in the formula we get

Δ v ≥ 6.626 × 10^−34Js / 4 x 3.14 x 9.11 x 10^-31 x 0.1 x 10^-10

Δ v ≥ 5.79 x 10^6 m/s

Answer 2

$\huge \tt \triangle x \geqslant 5.79 \times {10}^{6} \: ms$