Question

If young's modulus of elasticity Y for a material is one and half times its rigidity coefficient G , the Poisson's ratio will be
(1) +2/3
(2)-1/4
(3)+1/4
(4)-2/3

Answer 1

Answer:

The answer is option (2): -1/4.

Explanation:

The Relation between young modulus, modulus of rigidity an poison ratio is given by:-

2(1+u)=E/G  ----(1)

Where;

u= poison’s ratio

E=modulus of elasticity

G=modulus of rigidity;

Given:

E=1 x1/2G = 3/2 G  -----(2)

So, by using I and 2 we get

2G(1+u)= 3/2 G

After cancellation:

4((1+u) = 3

4 + 4u = 3

4u = 3-4

4u = -1

U= -1/4  

Answer 2

Answer:

See the attachment

Good luck

Explanation: