If young's modulus of elasticity Y for a material is one and half times its rigidity coefficient G , the Poisson's ratio will be
(1) +2/3
(2)-1/4
(3)+1/4
(4)-2/3
Answers
Answered by
51
Answer:
The answer is option (2): -1/4.
Explanation:
The Relation between young modulus, modulus of rigidity an poison ratio is given by:-
2(1+u)=E/G ----(1)
Where;
u= poison’s ratio
E=modulus of elasticity
G=modulus of rigidity;
Given:
E=1 x1/2G = 3/2 G -----(2)
So, by using I and 2 we get
2G(1+u)= 3/2 G
After cancellation:
4((1+u) = 3
4 + 4u = 3
4u = 3-4
4u = -1
U= -1/4
Answered by
11
Answer:
See the attachment
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Explanation:
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