Question

if young's molecules y surface tension s and time t are fundamental quantities then the dimension formula for density?​

Answer 1

Explanation:

please mark as brainliest answer..

Answer 2

Answer:

Dimension formula for density is  $y^{3} s^{-2} t^{2}$.

Step by step explanation:

• Young's modulus = $[ML^{-1}T^{-2} ]$
• Surface tension = $[MT^{-2} ]$
• Time = $[T]$

  We know that,

          Density =  $y^{a} s^{b} t^{c}$

          $[ML^{-3} ] = [ML^{-1}T^{-2} ]^{a} [MT^{-2} ]^{b} [T]^{c}$

          $[M][L]^{-3 = [M ]^{a+b} [L]^{-a} [T]^{-2a-2b+c}$

  On comparing the powers of the both sides,

  From the powers of [L],

     We get,  $-a=-3$          

           ∴          $a=3$

From the powers of [M],

                     $a+b=1$

                   $(3)+b=1$

            ∴             $b=-2$

From The powers of [T],

                    $-2a-2b+c=0$

             $-2(3)-2(-2)+c=0$

                         $-6+4+c=0$

          ∴                           $c=2$

Thus, Dimension formula for density is  $y^{3} s^{-2} t^{2}$.