Question

If your actual yield in an experiment was 20.0 grams of H2O and your theoretical yield was 54.1 grams of H2O what would be your percent yield? (write just the number)

Answer 1

Explanation:

Sample CalculationTheoretical yield of product=12.641 g Na2S2O3x (1 mol 12.641 g Na2S2O3 / 126 g) x (1 mol Na2S2O3·5H2O / 1 mol Na2S2O3) = 0.1003254 mol Na2S2O3·5H2O0.1003254 mol Na2S2O3·5H2O x 248 g Na2S2O3·5H2O = 24.88 gPercentage yield= (10.391 g / 24.88 g) x 100 = 41.76%Discussion The theoretical yield of Na2S2O3· ...