If ∠YTB ≡∠YBT and ∠BOY≡ ∠TRY,
prove that ∆BOY ≡ ∆TRY
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We know that ∠O = ∠R
and ∠TYR will be equal to ∠BYO for sure
and the angle sum of a triangle says that sume of all angles of a triangle are same, the ∠OBY = ∠RTY
Hence, 3 angles are equal, then using the AA congurence, we can say that ∆BOY is congurent to ∆TRY
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