Question

if z =1/2(i√3-1),then the value of (z-z²+2z³)*(2-z+z²) is​

Answer 1

Answer:

7

Step-by-step explanation:

z=1/2(i√3-1)

z²= -1/2(√3i+1)

z³=z²z=1 ( on solving)

z-z²+2z³= i√3/2-1/2- [-1/2(i√3+1)] +2×1 = A

= i√3/2-1/2+√3i/2+1/2 +2×1

=√3i+2

2-z+z²= 2-i√3/2+1/2-i√3/2-1/2 =B

= 2-i√3

now according to question we have to find out A × B

(2+i√3)×(2-i√3)

using a²-b²

we get answer 7