If z=1-i , find the imaginary part of z^6
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Answer:
-8
Step-by-step explanation:
(1+i)^6= ((1+i)^2)^3=(1+i²+2i)^3=(1-1+2i)^3=(2i)^3=8i³=8*i²*i=8*-1*i=-8i
so imaginary part= -8
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