If z = 1+ i, then arg (z)
Answers
Answered by
1
Answer:
Let w=z
2
e
z−i
Put z=1+i
⇒w=(1+i)
2
e
1+i−i
=(1+2i+i
2
)e
=(1+2i−1)e=2ei
Now, argument of w=arg(w)
=tan
−1
(
0
2e
)=tan
−1
∞=
2
π
Answered by
4
Answer:
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