If ∣z∣=1,(z≠−1)&z=x+iy then (z−1z+1) is
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∣z∣=1,(z≠−1)
&
z=x+iy
(z−1z+1) = ?
= 1
because Z=1Z
so both gets canceled and the answer will be 1.
∣z∣=1,(z≠−1)
&
z=x+iy
(z−1z+1) = ?
= 1
because Z=1Z
so both gets canceled and the answer will be 1.
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