if z=2+√3i find the value of z^2
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z=2+√3i
or, z² = (2+√3i)²
= 2²+2×2×√3i + (√3i)²
= 4+4√3i + 3i²
= 4+4√3i+3×-1
= 4+4√3i-3
= 1+4√3i Ans.
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