Math, asked by allwinraja7126236, 1 year ago

if z=2-3i, show that z^2-4z+13=0 and hence prove that4 z^3-3 z^2+169=0​

Answers

Answered by joshiyash3
10

Answer:

Hello there!

Step-by-step explanation:

These types of questions are very easy, so don't  get sacred by looking into the powers or the equation.

In every ques, the "given" condition includes the answer, so always try to figure out how you can work with the given condition i.e z=2-3i

Simply, squaring z, we get = 4+ 9i^2 -12i

                                          Z^2  = -5 -12i

Now just put the values in the eqn, i.e 4z = 8-12i

SO, we got= -5i -12i -(8-12i) +13 =0

So, try the nxt one yourself. I am sure u will get the answer now.

Hope it helps !


siddhivinayak194: I don't understanding what you do in solution plZ make to easy to understand
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