if z=2-3i, show that z^2-4z+13=0 and hence prove that4 z^3-3 z^2+169=0
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Answer:
Hello there!
Step-by-step explanation:
These types of questions are very easy, so don't get sacred by looking into the powers or the equation.
In every ques, the "given" condition includes the answer, so always try to figure out how you can work with the given condition i.e z=2-3i
Simply, squaring z, we get = 4+ 9i^2 -12i
Z^2 = -5 -12i
Now just put the values in the eqn, i.e 4z = 8-12i
SO, we got= -5i -12i -(8-12i) +13 =0
So, try the nxt one yourself. I am sure u will get the answer now.
Hope it helps !
siddhivinayak194:
I don't understanding what you do in solution plZ make to easy to understand
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