Question

if z=2-3i then z^(-1) is ?​

Answer 1

Answer:

z=(2−3i)

z

2

−4z+13

=(2−3i)

2

−4(2−3i)+13

=−5−12i−8+12i+13

=−12i+12i−5−8+13

=0

4z

3

−3z

2

+2z+170

=4(2−3i)

3

−3(2−3i)

2

+2(2−3i)+170

=4(−46−9i)−3(−5−12i)+2(2−3i)+170

=−184−36i−3(−5−12i)+2(2−3i)+170

=−184−36i+15+36i+4−6i+170

=5−6i