Question

if |z|=2, arg z=π÷6 then then z=?​

Answer 1

Step-by-step explanation:

For  any complex number

z=∣z∣ei.arg(z)

Here ∣z∣=2 and arg(z)=6π.

Hence, z=∣z∣ei.arg(z)

=2ei6π

=2(cos(6π)+isin(6π))

=2(23+i)

=3+i