Question

If z= 28 cm , m= 20 cm , mean =? *

Answer 1

Explanation:

It is given that ,

It is given that ,z - M = 2.5

It is given that ,z - M = 2.5=> M = z - 2.5 ---( 1 )

It is given that ,z - M = 2.5=> M = z - 2.5 ---( 1 )and x = 20

It is given that ,z - M = 2.5=> M = z - 2.5 ---( 1 )and x = 20*****************************************

It is given that ,z - M = 2.5=> M = z - 2.5 ---( 1 )and x = 20*****************************************By Empharical Formula :

It is given that ,z - M = 2.5=> M = z - 2.5 ---( 1 )and x = 20*****************************************By Empharical Formula :if mode = z , Median = M , mean = x

It is given that ,z - M = 2.5=> M = z - 2.5 ---( 1 )and x = 20*****************************************By Empharical Formula :if mode = z , Median = M , mean = xthen

It is given that ,z - M = 2.5=> M = z - 2.5 ---( 1 )and x = 20*****************************************By Empharical Formula :if mode = z , Median = M , mean = xthenz = 3M - 2x

It is given that ,z - M = 2.5=> M = z - 2.5 ---( 1 )and x = 20*****************************************By Empharical Formula :if mode = z , Median = M , mean = xthenz = 3M - 2x****************************************

It is given that ,z - M = 2.5=> M = z - 2.5 ---( 1 )and x = 20*****************************************By Empharical Formula :if mode = z , Median = M , mean = xthenz = 3M - 2x****************************************Now ,

It is given that ,z - M = 2.5=> M = z - 2.5 ---( 1 )and x = 20*****************************************By Empharical Formula :if mode = z , Median = M , mean = xthenz = 3M - 2x****************************************Now ,z = 3M - 2x

It is given that ,z - M = 2.5=> M = z - 2.5 ---( 1 )and x = 20*****************************************By Empharical Formula :if mode = z , Median = M , mean = xthenz = 3M - 2x****************************************Now ,z = 3M - 2x=> z = 3 ( z - 2.5 ) - 2 × 20

It is given that ,z - M = 2.5=> M = z - 2.5 ---( 1 )and x = 20*****************************************By Empharical Formula :if mode = z , Median = M , mean = xthenz = 3M - 2x****************************************Now ,z = 3M - 2x=> z = 3 ( z - 2.5 ) - 2 × 20=> z = 3z - 7.5 - 40

It is given that ,z - M = 2.5=> M = z - 2.5 ---( 1 )and x = 20*****************************************By Empharical Formula :if mode = z , Median = M , mean = xthenz = 3M - 2x****************************************Now ,z = 3M - 2x=> z = 3 ( z - 2.5 ) - 2 × 20=> z = 3z - 7.5 - 40=> z = 3z - 47.5

It is given that ,z - M = 2.5=> M = z - 2.5 ---( 1 )and x = 20*****************************************By Empharical Formula :if mode = z , Median = M , mean = xthenz = 3M - 2x****************************************Now ,z = 3M - 2x=> z = 3 ( z - 2.5 ) - 2 × 20=> z = 3z - 7.5 - 40=> z = 3z - 47.5=> z - 3z = - 47.5

It is given that ,z - M = 2.5=> M = z - 2.5 ---( 1 )and x = 20*****************************************By Empharical Formula :if mode = z , Median = M , mean = xthenz = 3M - 2x****************************************Now ,z = 3M - 2x=> z = 3 ( z - 2.5 ) - 2 × 20=> z = 3z - 7.5 - 40=> z = 3z - 47.5=> z - 3z = - 47.5=> z = ( - 47.5 )/( -3 )

It is given that ,z - M = 2.5=> M = z - 2.5 ---( 1 )and x = 20*****************************************By Empharical Formula :if mode = z , Median = M , mean = xthenz = 3M - 2x****************************************Now ,z = 3M - 2x=> z = 3 ( z - 2.5 ) - 2 × 20=> z = 3z - 7.5 - 40=> z = 3z - 47.5=> z - 3z = - 47.5=> z = ( - 47.5 )/( -3 )=> z = 23.75

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