if z=2x²y-y²x+3y then value of zyy at(3,-2) is
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Answer:
The answer is ( -6)
Step-by-step explanation:
z= 2x²y-y²x+3y
differentiating both side with respect to y
zy = 2x²-2yx +3
Again differentiating both side with respect to y
zyy = 0-2x +0 = -2x
at (3,-2)
zyy = -2×3 = -6
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