Question

if z=2x²y-y²x+3y then value of zyy at(3,-2) is​

Answer 1

Answer:

The answer is ( -6)

Step-by-step explanation:

z= 2x²y-y²x+3y

differentiating both side with respect to y

zy = 2x²-2yx +3

Again differentiating both side with respect to y

zyy = 0-2x +0  = -2x

at (3,-2)

zyy = -2×3  = -6