if Z= √3/2+i/2, Z³ then equals
a. i
b. -i
c. -1
d. 1
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Answer Correct option is
A
−1
z=23+2i=cos6π+isin6π
⇒z5=cos65π+isin65π=2−3+i
and z8=cos34π+isin34π=−(21+i3)
⇒(1+iz+z5+iz8)9=(1+2i3−21−23
Step-by-step explanation:
Correct option is
A
−1
z=23+2i=cos6π+isin6π
⇒z5=cos65π+isin65π=2−3+i
and z8=cos34π+isin34π=−(21+i3)
⇒(1+iz+z5+iz8)9=(1+2i3−21−23
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