Question

If z = 3 – 2
i then show that

z2
– 6
z + 13 = 0. Hence, find the value of z4
– 4
z3
+ 6
z2
– 4
z + 17.​

Answer 1

Sry I don’t know but pls mark brainliest and follow me

Answer 2

Answer:

5-6i

Step-by-step explanation:

z=(2−3i)

z

2

−4z+13

=(2−3i)

2

−4(2−3i)+13

=−5−12i−8+12i+13

=−12i+12i−5−8+13

=0

4z

3

−3z

2

+2z+170

=4(2−3i)

3

−3(2−3i)

2

+2(2−3i)+170

=4(−46−9i)−3(−5−12i)+2(2−3i)+170

=−184−36i−3(−5−12i)+2(2−3i)+170

=−184−36i+15+36i+4−6i+170

=5−6i