Question

if z= 3-5i then prove that z3-10+58z-136=0​

Answer 1

Answer:

z³=(3-5i)³=27-135i - 150+125i

.so,

z³-10+58z-136

= 27-135i-150+125i-10+174-290i-136

= -95-300i

Answer 2

Answer:

Step-by-step explanation: