Question

if z=√3+I/2 then (z^101+i^103)^105 is equal to​

Answer 1

Answer:

solved

Step-by-step explanation:

z = √3/2 + i/2 = cos π/6 + isinπ/6 = e^iπ/6

N = ( z^101 + i^103)^105 =  ( e^101iπ/6 + i^3)^105 =  ( e^5iπ/6 - i )^105

N = (-√3/2 + i/2 - i)^105 =  (-√3/2 - i/2  )^105 = (e^7iπ/6)∧105

N = e^735iπ/6 = e^iπ/2 = cosπ/2 + isinπ/2 = i

choose ans. → (d)

Answer 2

Answer:

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