If z=√-5 then what is the imaginary part?
Answers
Answered by
1
ANSWER IS 4.
EXPLANATION:)
z is a non-real complex number.
let z=re
iθ
(Imz)
5
Imz
5
=
r
5
sin
5
θ
r
5
sin5θ
say, f(θ)=
sin
5
θ
sin5θ
equating first derivative to 0
f
′
(θ)=0
⇒sin
5
θ⋅5cos5θ−sin5θ⋅5sin
4
θ⋅cosθ
⇒sinθ⋅cos5θ=cosθ⋅sin5θ
⇒tanθ=tan5θ
⇒θ=0,π/4...
but f(0) is indeterminate
f(π/4)=−4
∴ Minimum value of
(Imz)
5
Imz
5
is −4
Answered by
1
ANSWER IS 4.
EXPLANATION:)
z is a non-real com
say, f(θ)=
sin
5
θ
sin5θ
equating first derivative to 0
f
′
(θ)=0
⇒sin
5
θ⋅5cos5θ−sin5θ⋅5sin
4
θ⋅cosθ
⇒sinθ⋅cos5θ=cosθ⋅sin5θ
⇒tanθ=tan5θ
⇒θ=0,π/4...
but f(0) is indeterminate
f(π/4)=−4
∴ Minimum value of
(Imz)
5
Imz
5
is −4
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