Question

if z+b=az+c/b, calculate the value of "c", when z=12, b=3 and a=14​

Answer 1

Question :

if z+b=az+c/b, calculate the value of "c", when z=12, b=3 and a=14

To find :

The value of c

Given Data :

z=12

b=3

a=14

Solution :

$\sf \small \: z + b = az + \frac{c}{b}$

Now we need to perform cross multiplication to get the variables easier

$\sf \small \: b(z + b) = az + c$

$\sf \small \: zb + {b}^{2} = az + c$

$\sf \small \: c = zb + b^{2} - az$

Now we need to put the values

$\sf \small \: c = 12 \times 3 + {3}^{2} - 14 \times 12$

$\sf \small \: c = 36 + 9 - 168$

$\sf \small \: c = 45 - 168$

$\sf \small \: c = - 123$

• So the value of c is - 123