if z is a complex number, show that z- z bar/2i is real
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Solution:
Suppose, your complex number z is A + Bi, so z bar is equal to A - Bi. Now, if you take Z - Z bar you will have 2Bi left.
Also, we know that 1/i = -i, so when we divide 2Bi by 2i, it will be 2Bi * (-2i), and finally it will be converted into i^2 which is 1.
So, you will get 4B as answer. Which is real
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