if z is a complex number then show that z - z bar/2i is real
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2
Answer:
If z is a complex number and z=bar(z), then prove that z is a purely real number. show that if |(z-3i)/(z+3i)|=1 then z is a real number.
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Step-by-step explanation:
let z be a complex num
to prove :( z-(bar)z)/2i is real
proof:
z=a+ib
then ,
z-((bar)z)/2i=( (a+ib)-(a-ib))/2i
= (a+ib-a-ib)/2i
=0/2i
=0
hence ,proved
NOT SURE ABOUT IT.
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