Question

If z is a purely imaginary number and lies on the positive direction ofy-axis then what is the argument of z?​

Answer 1

Answer:

Square root of imaginary value.

Step-by-step explanation:

Z = 0 + iy (purely imaginary) and (z in +ve y axis)

Argument of Z is Square root of sum of squares of real and imaginary value , since real value is 0 and imaginary value is (some value) y.

Argument is $\sqrt{y+1}$ = $\sqrt{y}$.